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Magnetic Effect of Current

NEET > Physics > Magnetic Effects of Current and Magnetism

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Overview content

Chapter Snapshot - Magnetic Effect of Current

Magnetic Effect of Current covers the production and behaviour of magnetic fields by electric currents and their interaction with moving charges and conductors. The chapter spans Biot-Savart law, Ampere's circuital law, magnetic field configurations (straight wire, circular loop, solenoid, toroid), the Lorentz force on moving charges, force on current-carrying conductors in uniform fields, force between parallel currents, torque on a current loop (magnetic dipole), the cyclotron, and the moving coil galvanometer. This is a formula-dense chapter requiring both conceptual clarity and numerical fluency.

✓ Use This To Plan Your First 2–3 Hours
Expected Questions (Typical)
Q
2-3
NEET regularly tests Biot-Savart applications (field at centre of loop, on axis), force on a moving charge in magnetic field, torque on a current loop, and moving coil galvanometer sensitivity. Questions on force between parallel wires and cyclotron frequency appear frequently.
Time Required (Practical)
⏱
10-12 hrs
Theory and derivations for Biot-Savart, Ampere's law, and solenoid/toroid take around 4 hrs. Lorentz force, cyclotron, and trajectory problems take around 3 hrs. Force on conductors, parallel wires, torque, and galvanometer take around 3-4 hrs. MCQ revision adds 1-2 hrs.
Difficulty Level
⚡
Moderate-High
The vector cross-product nature of both Biot-Savart law and the Lorentz force makes direction determination tricky. Sign conventions for force direction (Fleming's left-hand rule) and correct identification of angles in the formulae are common error sources.
Most Asked Style: Numerical problems asking for magnetic field at the centre or axis of a circular loop, force between parallel wires, radius of circular path of a charged particle in a magnetic field, and torque on a current loop. Conceptual MCQs on galvanometer sensitivity and cyclotron frequency also appear.Biggest Trap: Confusing the angle in F = qvB sin(theta) with the angle in the Biot-Savart expression dB = (mu_0/4pi)(i dl sin(theta)/r^2). In the force formula, theta is between velocity and field vectors. In Biot-Savart, theta is between the current element and the position vector to the field point.Fast Win: Memorise: (i) B at centre of circular loop = mu_0 Ni / 2r; (ii) B inside infinite solenoid = mu_0 ni; (iii) r = mv/qB for circular path radius; (iv) Torque = NBiA sin(theta). These four results cover roughly 60% of NEET questions from this chapter.Revision-Friendly: Draw the right-hand rule diagrams for all three contexts: field around a wire, field of a circular loop, and force on a moving charge. One page of direction rules anchors the entire chapter.

Subtopics - Magnetic Effect of Current (NEET)

Magnetic fields from currents, forces on charges and conductors, and electromagnetic devices

Revision tip: Build your revision around four pillars: (1) Biot-Savart law and its standard results for wire, loop, and solenoid; (2) Lorentz force and charged particle trajectories; (3) force between parallel current-carrying wires; (4) torque on a current loop and galvanometer. Master the direction rules first, then the magnitudes follow naturally.
NCERT LinesMCQsQuick Test

1) Biot-Savart Law and Magnetic Field Configurations

Biot-Savart law for the magnetic field due to a current element, direction rules (Maxwell's cork screw, right-hand thumb rule), magnetic field due to a straight conductor (finite, infinite, semi-infinite), circular current loop (centre, axial point, arcs), Helmholtz coils, and concentric coplanar loops.

dB = (mu_0/4pi)(i dl sin theta / r^2)B_centre = mu_0 Ni / 2rB_axis = (mu_0/4pi)(2pi Ni r^2)/(x^2+r^2)^(3/2)Infinite wire: B = mu_0 i / 2pi rArc angle theta: B = mu_0 i theta / 4pi r
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Biot-Savart Law and Current ElementDefinition of current element i dl, the Biot-Savart expression in scalar and vector forms, units of magnetic field (tesla, gauss), and the condition for zero field along the axis of the wire.
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Direction of Magnetic FieldMaxwell's cork screw rule, right-hand thumb rule for straight conductors, right-hand thumb rule for circular currents, right-hand palm rule, and the cross/dot convention for perpendicular fields.
›
Magnetic Field Due to a Straight WireGeneral formula B = (mu_0/4pi)(i/r)(sin phi_1 + sin phi_2) for a finite wire, infinite wire result B = mu_0 i / 2pi r, semi-infinite wire result B = mu_0 i / 4pi r, and the zero field on the axial line of the wire.
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Magnetic Field Due to Circular CurrentField at the centre B = mu_0 Ni / 2r, field on the axis, B-x variation curve, point of inflection at x = r/2, Helmholtz coils arrangement and midpoint field, and field due to arcs subtending angle theta at the centre.
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Concentric Coplanar Loops and Special CasesNet field for concentric loops carrying current in same or opposite directions, perpendicular coplanar loops (vector addition of fields), and the zero-field result when current distributes symmetrically across a diameter.

2) Ampere's Circuital Law and Its Applications

Ampere's circuital law statement and mathematical form, comparison with Biot-Savart law, magnetic field due to cylindrical conductors (solid, thin hollow, thick hollow), infinite current sheet, solenoid (finite and infinite), and toroid.

Line integral B . dl = mu_0 (sum i)B_solenoid = mu_0 n iB_toroid = mu_0 N i / 2pi rB_inside solid cylinder = (mu_0 i r)/(2pi R^2)B_inside hollow = 0
›
Ampere's Circuital LawStatement of the law: line integral of B around a closed loop equals mu_0 times the net enclosed current. Sign convention for current direction (outward positive, inward negative). Comparison with Gauss's law in electrostatics.
›
Magnetic Field of Cylindrical ConductorsSolid cylinder: B_out = mu_0 i / 2pi r, B_surface = mu_0 i / 2pi R, B_in = mu_0 i r / 2pi R^2. Thin hollow cylinder: B_in = 0. Thick hollow cylinder: B in the thick region depends on (r^2 minus R_1^2)/(R_2^2 minus R_1^2).
›
SolenoidFinite solenoid field using Ampere's law with angular limits. Infinite solenoid: B_in = mu_0 n i (uniform inside), B_end = (1/2) mu_0 n i. Field outside an ideal infinite solenoid is zero.
›
ToroidRing-shaped closed solenoid. B = mu_0 N i / 2pi r inside the toroid where N is total turns. Equivalent to B = mu_0 n i with n = N / 2pi r. Field is zero both inside the central hole and outside the toroid.
›
Infinite Current SheetFor a sheet with linear current density j (A/m), Ampere's law gives B = mu_0 j / 2 on each side, directed parallel to the sheet surface. Derivation using a rectangular Amperian loop.

3) Force on Moving Charges and Current-Carrying Conductors

Magnetic force on a moving charge (F = qvB sin theta), Lorentz force, trajectory of charged particles (straight line, circular, helical), cyclotron, velocity selector, Hall effect, force on a current-carrying conductor (F = BiL sin theta), force between parallel conductors, and standard equilibrium cases.

F = qvB sin thetar = mv/qBT = 2pi m/qBLorentz: F = q(E + v x B)F/l = mu_0 i_1 i_2 / 2pi aCyclotron: nu = qB/2pi m
›
Force on a Moving ChargeF = q(v x B); magnitude F = qvB sin theta. Zero force when v is parallel to B, charge is neutral, or charge is stationary. Direction by Fleming's left-hand rule. Force is always perpendicular to velocity, so magnetic force does no work and kinetic energy stays constant.
›
Trajectory of Charged ParticleParallel to B: straight line. Perpendicular to B: circular path with r = mv/qB, T = 2pi m/qB (independent of speed). At arbitrary angle: helical path with radius r = mv sin theta / qB and pitch p = 2pi mv cos theta / qB.
›
Lorentz Force and Velocity SelectorCombined electric and magnetic fields: F = q(E + v x B). When E and B are perpendicular and qE = qvB, net force is zero and the particle passes undeflected. Selected velocity v = E/B. This principle is the basis of the velocity selector.
›
CyclotronDevice to accelerate positive ions using crossed electric and magnetic fields. Two D-shaped dees with alternating electric field. Cyclotron frequency nu = qB/2pi m (independent of speed and radius). Maximum kinetic energy E_max = q^2 B^2 r_0^2 / 2m. Cannot accelerate electrons (too light, relativistic effects dominate) or neutral particles.
›
Force on Current-Carrying ConductordF = i(dl x B); for a straight wire in uniform field F = BiL sin theta. Direction by Fleming's left-hand rule or right-hand palm rule. For a closed loop in a uniform field, net force is zero.
›
Force Between Parallel ConductorsF/l = mu_0 i_1 i_2 / 2pi a. Same direction currents attract; opposite direction currents repel. This defines the SI unit of ampere: 1 A is the current in each of two infinitely long parallel wires 1 m apart that produces a force of 2 x 10^(minus 7) N per metre.
›
Hall EffectTransverse EMF produced when a current-carrying conductor is placed in a perpendicular magnetic field. Determines the nature (positive or negative) and number density of charge carriers. Hall voltage V_H = Bi/net where n is charge carrier density, e is charge, and t is thickness.

4) Torque on Current Loop and Moving Coil Galvanometer

Current loop as a magnetic dipole, magnetic moment M = NiA, torque on a loop in uniform field, work done in rotating a loop, potential energy of a magnetic dipole, moving coil galvanometer construction, deflection relation, current sensitivity, and voltage sensitivity.

M = NiATorque = NiAB sin thetatau = M x BW = MB(1 minus cos theta)Galvanometer: i = (C/NBA) alphaS_i = NBA/CS_V = NBA/RC
›
Current Loop as Magnetic DipoleMagnetic moment M = NiA where N is the number of turns, i is the current, and A is the area of the loop. Direction is given by the right-hand thumb rule. For a given perimeter, a circular loop gives the maximum magnetic moment. B at the centre and M are always parallel.
›
Torque on a Current LoopTorque tau = NiAB sin theta where theta is the angle between the area vector (normal to loop) and B. In vector form tau = M x B. Torque is zero when the loop plane is perpendicular to B (theta = 0) and maximum when the plane is parallel to B (theta = 90 degrees).
›
Work and Potential EnergyWork done to rotate the loop from equilibrium by angle theta: W = MB(1 minus cos theta). Maximum work at theta = 180 degrees gives W_max = 2MB. Potential energy U = minus M dot B = minus MB cos theta. Stable equilibrium at theta = 0, unstable at theta = 180 degrees.
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Moving Coil GalvanometerCoil suspended between cylindrical pole pieces with a soft iron core to make the field radial. Deflecting torque tau = NiAB balanced by restoring torque C alpha. Current i = (C/NBA) alpha = K alpha. Current sensitivity S_i = alpha/i = NBA/C. Voltage sensitivity S_V = NBA/RC. Increasing N or B raises S_i but does not necessarily improve S_V because resistance also increases.

Magnetic Effect of Current Download Notes & Weightage Plan

For each topic in the Magnetic Effect of Current chapter below, you get (2) the exact resources to download and how to use them, and (3) a simple importance & time plan so NEET students know what to do first and what to revise last.

2 Downloads

Biot-Savart Law and Magnetic Field Configurations

Biot-Savart law, direction rules, field of straight wire, circular loop (centre and axis), arcs, Helmholtz coils, and concentric loops.

dB = (mu_0/4pi)(i dl sin theta / r^2)B_centre = mu_0 Ni / 2rInfinite wire: mu_0 i / 2pi rArc: mu_0 i theta / 4pi rHelmholtz midpoint: 0.716 mu_0 Ni / R

1) Download Packs For This Topic (And How To Use Them)

Don't download everything and forget it. Use these like a small "attack kit": read → highlight → test → revise the same sheet again.

↓
Topic Notes (Condensed)Biot-Savart law: dB = (mu_0/4pi)(i dl sin theta / r^2) in scalar form; vector form uses dl cross r-hat. Field is zero on the line of the wire (theta = 0 or pi). Straight wire: B = (mu_0/4pi)(i/r)(sin phi_1 + sin phi_2); infinite wire phi_1 = phi_2 = 90 gives B = mu_0 i / 2pi r; semi-infinite gives half this value. Circular loop centre: B = mu_0 Ni / 2r; on axis: B = (mu_0 Ni r^2) / 2(x^2 + r^2)^(3/2). For x >> r, B_axis proportional to 1/x^3 (dipole field). Arc subtending angle theta: B = mu_0 i theta / 4pi r. Helmholtz coils: two identical coils separated by radius R, midpoint field = 0.716 mu_0 Ni / R.
Download NotesPrintable PDF
★
NCERT Key Lines (One-Liners)These are the lines NEET converts into "statement is correct/incorrect" questions.
NCERT LinesFlashcards
Q
Practice Set (MCQs + PYQs)Do 30–50 questions, then mark errors as "memory miss" or "confusion between options."
MCQ SetPYQs
How to revise: Derive the straight wire formula step by step. Then write all five standard results: infinite wire, semi-infinite wire, centre of loop, axis of loop, and arc. Draw the B-x curve for a circular coil and mark the inflection points at x = r/2. Solve 8 to 10 MCQs on field at centre of arcs.

2) Importance, Weightage & Time Allocation (Practical)

Use this to avoid over-studying. This topic is usually low effort, quick return if your recall is clean.

Expected Questions1NEET commonly asks for the magnetic field at the centre of a loop or due to an arc subtending a given angle. Straight wire formula applications also appear.
Time Required3 hrs1.5 hrs for theory and derivation, 1.5 hrs for numerical practice on all standard configurations.
DifficultyModerateThe Biot-Savart integral is conceptually straightforward but applying it to different geometries requires careful angle identification. The arc formula is a fast-win shortcut.
  • Scoring Focus: B at centre of circular loop = mu_0 Ni / 2r; arc formula B = mu_0 i theta / 4pi r; infinite wire B = mu_0 i / 2pi r. These three cover most NEET questions.
  • High-risk Area: Confusing the angle theta in Biot-Savart (angle between dl and r) with other angles in the problem geometry. Also forgetting the factor of N (number of turns) in the loop formula.
  • Best Practice Style: Direct numerical application of standard results; finding resultant field at centre of concentric arcs.
Priority rule: Start here as this provides the foundational field expressions used in all subsequent topics.

Ampere's Circuital Law and Its Applications

Ampere's law statement, magnetic field in cylindrical conductors, solenoid, toroid, and infinite current sheet.

Integral B.dl = mu_0 i_enclosedB_solenoid = mu_0 niB_end = (1/2) mu_0 niB_toroid = mu_0 Ni / 2pi rHollow cylinder: B_inside = 0

1) Download Packs For This Topic (And How To Use Them)

Don't download everything and forget it. Use these like a small "attack kit": read → highlight → test → revise the same sheet again.

↓
Topic Notes (Condensed)Ampere's law: line integral of B around closed path = mu_0 times net enclosed current. Analogous to Gauss's law. Best for high-symmetry configurations. Solid cylinder: B_outside = mu_0 i / 2pi r; B_inside = mu_0 i r / 2pi R^2 (linear in r). Hollow cylinder: B = 0 inside. Infinite solenoid: B_in = mu_0 n i (uniform, only inside); B_end = half of B_in. Toroid: B = mu_0 N i / 2pi r (inside), zero outside and in the central hole. Current sheet: B = mu_0 j / 2.
Download NotesPrintable PDF
★
NCERT Key Lines (One-Liners)These are the lines NEET converts into "statement is correct/incorrect" questions.
NCERT LinesFlashcards
Q
Practice Set (MCQs + PYQs)Do 30–50 questions, then mark errors as "memory miss" or "confusion between options."
MCQ SetPYQs
How to revise: Draw the B-vs-r graph for solid and hollow cylinders side by side. Memorise: inside solid cylinder B is proportional to r; outside B is proportional to 1/r. Write solenoid and toroid results and practise 5 problems on each.

2) Importance, Weightage & Time Allocation (Practical)

Use this to avoid over-studying. This topic is usually low effort, quick return if your recall is clean.

Expected Questions0-1Solenoid and toroid field values are standard NEET questions. The solid vs hollow cylinder B variation is a frequent conceptual MCQ.
Time Required2 hrs1 hr for Ampere's law derivations (cylinder + solenoid + toroid), 1 hr for MCQ practice.
DifficultyModerateApplying Ampere's law requires choosing the correct Amperian loop. The toroid formula with r-dependence can confuse students who expect a uniform field like a solenoid.
  • Scoring Focus: B_solenoid = mu_0 n i (inside, uniform); B at end = half; toroid = mu_0 Ni / 2pi r; hollow cylinder B = 0 inside.
  • High-risk Area: Assuming field inside a toroid is uniform like a solenoid. The toroid field varies as 1/r. Also forgetting that field outside an ideal solenoid is zero.
  • Best Practice Style: Conceptual MCQs on B variation graphs; direct substitution numericals for solenoid and toroid.
Priority rule: Cover after Biot-Savart. Solenoid and toroid results are frequently tested and quick to learn.

Force on Moving Charges and Current-Carrying Conductors

Lorentz force, charged particle trajectories, cyclotron, velocity selector, force on wire, force between parallel conductors, Hall effect.

F = qvB sin thetar = mv/qBT = 2pi m/qBCyclotron freq = qB/2pi mF/l = mu_0 i_1 i_2 / 2pi av = E/B (selector)

1) Download Packs For This Topic (And How To Use Them)

Don't download everything and forget it. Use these like a small "attack kit": read → highlight → test → revise the same sheet again.

↓
Topic Notes (Condensed)Force on moving charge: F = q(v x B); magnitude qvB sin theta. Zero when v parallel to B or charge at rest. Circular path: r = mv/qB = p/qB = sqrt(2mK)/qB = (1/B)sqrt(2mV/q). Time period T = 2pi m/qB (independent of v). Helical path when v is at angle theta to B: radius uses v sin theta, pitch uses v cos theta. Lorentz force: F = q(E + v x B). Velocity selector: v = E/B when qE = qvB. Cyclotron: nu = qB/2pi m; E_max = q^2 B^2 r_0^2 / 2m; cannot accelerate electrons or neutrals. Force on conductor: F = BiL sin theta. Closed loop in uniform field: net force = 0. Parallel wires: F/l = mu_0 i_1 i_2 / 2pi a; same direction attracts, opposite repels. Defines the ampere.
Download NotesPrintable PDF
★
NCERT Key Lines (One-Liners)These are the lines NEET converts into "statement is correct/incorrect" questions.
NCERT LinesFlashcards
Q
Practice Set (MCQs + PYQs)Do 30–50 questions, then mark errors as "memory miss" or "confusion between options."
MCQ SetPYQs
How to revise: Memorise the four expressions for radius r in terms of momentum, kinetic energy, and accelerating potential. Derive T = 2pi m/qB from r = mv/qB. Practice 5 cyclotron problems and 5 parallel wire force problems. Solve 3 helical path problems calculating radius and pitch.

2) Importance, Weightage & Time Allocation (Practical)

Use this to avoid over-studying. This topic is usually low effort, quick return if your recall is clean.

Expected Questions1-2NEET heavily tests radius of circular path, time period independence from speed, force between parallel wires, and cyclotron frequency. This is the highest-yield topic in the chapter.
Time Required3.5 hrs1.5 hrs for theory (Lorentz force + trajectories + cyclotron), 2 hrs for numerical practice across all subtopics.
DifficultyModerate-HighVector cross products require direction determination using Fleming's left-hand rule. The four different expressions for radius confuse students who fail to identify which quantity is given.
  • Scoring Focus: r = mv/qB and T = 2pi m/qB (circular path); cyclotron frequency independent of speed; F/l = mu_0 i_1 i_2 / 2pi a and the definition of ampere.
  • High-risk Area: Forgetting that magnetic force does zero work (kinetic energy unchanged). Confusing the four radius expressions. Applying wrong direction rule. Also: cyclotron cannot accelerate electrons (they require synchrotron due to relativistic mass increase).
  • Best Practice Style: Numerical MCQs on radius and time period; conceptual MCQs on force direction; cyclotron energy calculation.
Priority rule: HIGHEST priority in this chapter. Covers the maximum number of NEET questions. Spend the most time here.

Torque on Current Loop and Moving Coil Galvanometer

Magnetic dipole moment, torque, work, potential energy, galvanometer principle, current sensitivity, voltage sensitivity.

M = NiAtau = NiAB sin thetaW = MB(1 minus cos theta)i = (C/NBA) alphaS_i = NBA/CS_V = NBA/RC

1) Download Packs For This Topic (And How To Use Them)

Don't download everything and forget it. Use these like a small "attack kit": read → highlight → test → revise the same sheet again.

↓
Topic Notes (Condensed)Magnetic moment M = NiA; direction by right-hand rule. Torque tau = NiAB sin theta = M x B. Maximum torque when loop plane is parallel to B. Zero torque when plane is perpendicular to B. Work W = MB(1 minus cos theta); W_max = 2MB at 180 degrees. Potential energy U = minus MB cos theta; stable at theta = 0, unstable at theta = 180. MCG: radial field ensures theta = 90 always, so tau = NiAB. Restoring torque = C alpha. At equilibrium i = (C/NBA) alpha. Current sensitivity S_i = NBA/C. Voltage sensitivity S_V = NBA/RC. Increasing N raises S_i but also raises R, so S_V may not improve.
Download NotesPrintable PDF
★
NCERT Key Lines (One-Liners)These are the lines NEET converts into "statement is correct/incorrect" questions.
NCERT LinesFlashcards
Q
Practice Set (MCQs + PYQs)Do 30–50 questions, then mark errors as "memory miss" or "confusion between options."
MCQ SetPYQs
How to revise: Derive tau = NiAB sin theta for a rectangular loop step by step. Write the energy table: theta = 0 (U = minus MB, stable), theta = 90 (U = 0), theta = 180 (U = +MB, unstable). Memorise galvanometer relations and solve 5 sensitivity-comparison MCQs.

2) Importance, Weightage & Time Allocation (Practical)

Use this to avoid over-studying. This topic is usually low effort, quick return if your recall is clean.

Expected Questions1NEET tests torque on a current loop, galvanometer sensitivity relations, and the effect of changing N, B, or A on sensitivity. Standard formula-application questions.
Time Required2 hrs45 min for torque and energy derivation, 45 min for galvanometer theory, 30 min for MCQ practice.
DifficultyModerateThe torque formula is clean. The main confusion is the angle: theta is between the normal to the loop (the area vector) and B, not between the plane of the loop and B.
  • Scoring Focus: tau = NiAB sin theta; galvanometer S_i = NBA/C; the fact that radial field keeps theta = 90 in the galvanometer.
  • High-risk Area: Confusing theta as the angle between the plane of the loop and B (it is the angle between the normal to the plane and B). Also: thinking voltage sensitivity always increases with current sensitivity (it does not, because resistance R also changes with N).
  • Best Practice Style: Torque calculation MCQs; galvanometer sensitivity comparison when parameters change.
Priority rule: Cover after the force topic. Torque and galvanometer together form one reliable NEET question every year.

Magnetic Effect of Current Chapter NEET Traps & Common Mistakes (Topic-Wise)

Each subtopic below is of the Magnetic Effect of Current chapter and shows what NEET students usually do wrong in NEET examination, a short example of the mistake, and how NEET frames the question to trick you with close options are given below.

! Avoid Easy Negatives
Biot-Savart Angle vs Lorentz Force Angle
Biot-Savart LawLorentz ForceAngle Confusion

Mistake Snapshot (What Students Do Wrong)

  • Swapping the angle definitions: In Biot-Savart, theta is the angle between the current element dl and the position vector r to the field point. In F = qvB sin theta, theta is between velocity v and magnetic field B. Students routinely substitute the wrong angle.
  • Ignoring sin theta = 0 on the axis: On the line of a current-carrying wire, theta = 0 or 180 degrees, making dB = 0. Students forget this and attempt to compute a nonzero field on the wire axis.
2–3 Line Example (Typical Error)

A current element of length dl carrying current i has a field point P on its axis (theta = 0). Applying Biot-Savart: dB = (mu_0/4pi)(i dl sin 0 / r^2) = 0. Students who confuse this angle with some other geometry angle get a nonzero answer and pick the wrong option.

How NEET Frames The Trap

NEET distractors include computed values assuming theta = 90 degrees when the point is actually on the wire axis. Always verify: is the field point on the line of the current element?

NEET-Style Trap Question Format

Q. The magnetic field at a point on the axis of a current-carrying straight conductor is:
A. mu_0 i / 2pi r   B. mu_0 i / 4pi r   C. mu_0 i / 4pi r^2   D. Zero  
Trick: On the axis of the wire, the angle between dl and r is 0 (or 180 degrees). Since sin 0 = 0, dB = 0 for every current element. The correct answer is D.

Quick rule: Biot-Savart theta is between dl and r. Lorentz theta is between v and B. On the wire axis, theta = 0 so B = 0 always.
Circular Path Radius Expressions
Moving ChargeCircular PathRadius Formula

Mistake Snapshot (What Students Do Wrong)

  • Using wrong radius expression for given data: Four forms exist: r = mv/qB = p/qB = sqrt(2mK)/qB = (1/B)sqrt(2mV/q). Students pick the momentum form when kinetic energy is given, or the velocity form when potential difference is given, leading to incorrect answers.
  • Forgetting T is independent of v: Time period T = 2pi m / qB depends only on mass, charge, and field strength. Students incorrectly assume faster particles take less time per revolution.
2–3 Line Example (Typical Error)

A proton accelerated through 100 V enters a 0.1 T field perpendicular to its velocity. Using r = (1/B)sqrt(2mV/q): r = (1/0.1)sqrt(2 x 1.67 x 10^(minus 27) x 100 / 1.6 x 10^(minus 19)) = 0.0144 m. A student who uses r = mv/qB without first computing v from the potential difference will get stuck or make an error.

How NEET Frames The Trap

NEET gives the accelerating potential (not the velocity) and expects you to use r = (1/B)sqrt(2mV/q) directly. Distractors are computed using wrong substitutions.

NEET-Style Trap Question Format

Q. A proton (mass m, charge q) is accelerated through potential V and enters a magnetic field B perpendicular to its velocity. The radius of its circular path is:
A. mv / qB   B. (1/B) sqrt(2mV/q)   C. qBV / 2m   D. sqrt(2qV) / mB  
Trick: Kinetic energy = qV, so (1/2)mv^2 = qV gives v = sqrt(2qV/m). Substituting in r = mv/qB yields r = (m/qB)sqrt(2qV/m) = (1/B)sqrt(2mV/q). Answer is B.

Quick rule: Match the radius formula to the given quantity: velocity given use mv/qB; momentum given use p/qB; KE given use sqrt(2mK)/qB; potential given use (1/B)sqrt(2mV/q).
Torque Angle Confusion in Current Loop
TorqueCurrent LoopAngle Error

Mistake Snapshot (What Students Do Wrong)

  • Using angle of plane instead of normal: Torque tau = NiAB sin theta where theta is between the normal to the loop and B. If the plane makes angle alpha with B, then theta = 90 minus alpha. Students who directly use alpha get cos alpha instead of sin theta.
  • Ignoring radial field in galvanometer: In a moving coil galvanometer the magnetic field is radial, so the plane of the coil is always parallel to B (theta = 90 degrees). Students sometimes substitute theta and get a sine factor when none exists.
2–3 Line Example (Typical Error)

A rectangular loop (N = 50, A = 0.04 m^2, i = 2 A) is placed in a 0.5 T field with the plane of the loop at 30 degrees to B. Theta (angle of normal with B) = 90 minus 30 = 60 degrees. Torque = 50 x 2 x 0.04 x 0.5 x sin 60 = 1.73 N m. Using sin 30 instead gives 1.0 N m, which is wrong.

How NEET Frames The Trap

NEET often states the angle of the plane (not the normal) with respect to B. The distractor is computed using sin of the given angle directly.

NEET-Style Trap Question Format

Q. A coil of 100 turns and area 0.01 m^2 carries 1 A in a 0.2 T field. The plane of the coil makes 60 degrees with B. The torque is:
A. 0.2 sin 60 = 0.173 N m   B. 0.2 sin 30 = 0.1 N m   C. 0.2 cos 60 = 0.1 N m   D. 0.2 cos 30 = 0.173 N m  
Trick: Plane at 60 degrees to B means the normal makes 90 minus 60 = 30 degrees with B. So tau = NiAB sin 30 = 100 x 1 x 0.01 x 0.2 x 0.5 = 0.1 N m. Answer is B.

Quick rule: If the problem gives the angle of the PLANE with B, subtract from 90 to get the angle of the NORMAL, then apply sin.
Galvanometer Sensitivity Trade-off
Moving Coil GalvanometerCurrent SensitivityVoltage Sensitivity

Mistake Snapshot (What Students Do Wrong)

  • Assuming S_V increases with N: Current sensitivity S_i = NBA/C increases with N. But voltage sensitivity S_V = NBA/RC = S_i/R. Since adding turns increases R proportionally, S_V may stay constant or even decrease. Students assume more turns always mean higher sensitivity for both.
  • Confusing K with S_i: The galvanometer constant K = C/NBA is the inverse of current sensitivity. A smaller K means higher sensitivity. Students sometimes set K equal to S_i, inverting the relationship.
2–3 Line Example (Typical Error)

Doubling the number of turns N from 50 to 100: S_i doubles (from NBA/C to 2NBA/C). But the coil resistance R also roughly doubles. So S_V = S_i/R stays approximately unchanged. Students who pick 'S_V doubles' lose the mark.

How NEET Frames The Trap

NEET asks what happens to voltage sensitivity when N is doubled. The expected wrong answer is that it doubles (just like current sensitivity).

NEET-Style Trap Question Format

Q. If the number of turns in a moving coil galvanometer is doubled keeping all other parameters same, the voltage sensitivity:
A. Doubles   B. Halves   C. Remains same   D. Becomes four times  
Trick: S_V = NBA/RC. Doubling N doubles both the numerator (NBA) and the denominator (R, since resistance is proportional to N for the same wire). So S_V remains approximately unchanged. Answer is C.

Quick rule: Current sensitivity S_i = NBA/C scales with N. Voltage sensitivity S_V = S_i/R. Since R also scales with N, S_V does not improve by simply adding turns.

Topics

Biot-Savart's Law

Magnetic Field Due to Circular Current

Magnetic Field Due to a Straight Wire

Force on Charged Particle in Magnetic Field

Solenoid and Toroid

Force on Current Carrying Conductors

Current Loop as a Magnetic Dipole

Moving Coil Galvanometer

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Current Electricity > Heating and Chemical Effect of Current > Thermo Electric Effect of Current > Applications of Thermo Electric Effect
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Biot-Savart's Law

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