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Force on Charged Particle in Magnetic Field

NEET > Physics > Magnetic Effects of Current and Magnetism > Magnetic Effect of Current > Force on Charged Particle in Magnetic Field

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Overview content

Topic 4 of 8 โ€ข Chapter: Magnetic Effect of Current โ€ข Physics

Force on Charged Particle in Magnetic Field โ€“ Complete Notes, Revision, Important Questions & Downloads

Force on Charged Particle in Magnetic Field starts with Lorentz Force and Trajectory, where the magnetic part of the force fixes whether motion is straight, circular, or helical, and then moves to Velocity Selector and Cyclotron, where the same force law becomes a device-level application. NEET uses this topic for direct formula questions on F = qvB sin theta, for geometry-based trajectory questions using r = mv/qB, and for selector or cyclotron conditions such as v = E/B and nu = qB/2pi m. A standard example is a proton entering a uniform magnetic field perpendicularly: the force changes only the direction of motion, so the path becomes circular while kinetic energy stays unchanged. Hall effect is usually tested as a linked application of transverse force on charge carriers rather than as an isolated definition.

โฌ‡ Download Notes PDFView Important Questions โ†’
Charged MotionTrajectory MathsNEET Core
Expected QuestionsQ
1-2
questions from trajectory geometry, selector condition, or cyclotron frequency
Time Requiredโฑ
4 Hours
to connect force direction, orbit formulae, and device applications without mixing cases
Difficultyโšก
Medium
formulas are standard, but angle geometry and charge-sign direction cause errors
NRI USA Curriculum GapUS
Moderate
many school tracks teach magnetic force qualitatively but do less timed drill on selector, cyclotron, and Hall-effect applications
2Subtopics
40+Practice Questions
4Free Downloads
4 hrsPrep Time
โฌ‡ Get Free Downloads

NEET Weightage & Exam Pattern

Magnetic Effect of Current
NEET YearQuestions from this TopicBarMarks
20241
ย 
1 Q
4
20232
ย 
2 Qs
8
20221
ย 
1 Q
4
20212
ย 
2 Qs
8
20201
ย 
1 Q
4
Topic Weightage7ย 28
NEET repeatedly tests the condition-based split: velocity parallel to B gives no magnetic deflection, velocity perpendicular to B gives circular motion, and an oblique velocity gives a helix.
Cyclotron frequency and velocity-selector speed are standard one-step formulas, but the trap is deciding which force balance is active in the given setup.

Hall effect questions are usually application-based, asking what transverse emf reveals about charge carriers rather than asking for a memorised definition alone.
๐Ÿ“Š
1.2
Avg Questions / Year
๐ŸŽฏ
28
Total Marks (6 yrs)
๐Ÿ“ˆ
Mixed
Pattern
โš ๏ธ
Medium
Difficulty

Preparation Strategy

1

Split the Motion by Angle First Before writing any formula, decide whether theta is 0 degree, 90 degree, or an intermediate value. That single geometry check tells you whether the path is straight, circular, or helical and prevents mixing r = mv/qB into a case where no magnetic deflection exists.

2

Use Perpendicular Force to Protect Energy Logic Memorise that magnetic force is always perpendicular to velocity, so in a pure magnetic field the speed, momentum magnitude, and kinetic energy stay unchanged. The trap is to think the particle speeds up because it is experiencing a force.

3

Keep Selector and Cyclotron Conditions Separate In a velocity selector, electric and magnetic forces cancel so qE = qvB and only one speed passes undeviated. In a cyclotron, the magnetic field bends the orbit while the alternating electric field accelerates the particle across the gap; do not merge these two devices into one formula set.

4

Assign Direction After Fixing the Charge Sign Find the direction for a positive charge first using the vector product or Fleming's left-hand convention, then reverse it for a negative charge. Many NEET errors come from using the correct rule with the wrong sign convention.

Download Topic Notes

PDF ยท Cheat Sheet ยท MCQ Set ยท PYQ
๐Ÿ“„
Full Topic Notes
Detailed notes on Lorentz force, trajectory cases, velocity selector, cyclotron, and Hall-effect interpretation.
PDF10 Pages
Download Notes
๐Ÿ“
Formula Sheet
One-page sheet for F = qvB sin theta, r = mv/qB, T = 2pi m/qB, v = E/B, and cyclotron frequency.
PDF1 Page
Download Formulas
๐ŸŽฏ
MCQ Practice
Practice set covering direction rules, helical motion, selector speed, cyclotron conditions, and Hall-effect basics.
PDF38 Questions
Download MCQs
โณ
Previous Year Questions
Selected PYQs on trajectory classification, crossed-field motion, and cyclotron-frequency interpretation.
PDF15 Questions
Download PYQs

Topic Coverage

2-Column Table
Column AColumn B
Lorentz Force and Trajectoryโ†—
Velocity Selector and Cyclotronโ†—

Quick Revision

Concept โ†’ Trap โ†’ Example

1) Lorentz Force and Trajectory

Motion Geometry

Magnetic force on a moving charge is F = q(v x B), with magnitude qvB sin theta. In a pure magnetic field this force stays perpendicular to velocity, so it changes direction of motion but does not change speed or kinetic energy.

  • If velocity is parallel or antiparallel to the field, magnetic force is zero and the particle keeps a straight-line path.
  • If velocity is perpendicular to the field, magnetic force acts as centripetal force and gives r = mv/qB and T = 2pi m/qB.
  • Trap: for an oblique entry, do not use the full speed in the radius formula; only the component perpendicular to B sets the circular part, while the parallel component builds the pitch of the helix.
Example (NEET-style)An alpha particle entering a uniform field B perpendicularly with speed v follows a circular path of radius mv/qB; if its speed doubles at the same B and q, the radius doubles, but the time period 2pi m/qB stays the same.

2) Velocity Selector and Cyclotron

Device Application

In crossed electric and magnetic fields, a charged particle passes undeflected only when qE = qvB, so the selected speed is v = E/B. In a cyclotron, the magnetic field bends the orbit while the alternating electric field accelerates the positive ion, giving nu = qB/2pi m and maximum kinetic energy q squared B squared r0 squared divided by 2m.

  • Cyclotron frequency depends on charge, magnetic field, and mass, but not on the speed or radius of the orbit in the non-relativistic treatment used for NEET.
  • Hall effect is the transverse emf produced when moving charge carriers are deflected sideways by a magnetic field perpendicular to the current.
  • Trap: cyclotron does not accelerate neutrons because q = 0, and it is not used for electrons in this school-level treatment because the simple constant-frequency condition breaks down at high speed.
Example (NEET-style)If E = 4 x 10^4 N/C and B = 0.02 T in a selector, only particles with v = E/B = 2 x 10^6 m/s move straight through; slower or faster particles curve because the two forces no longer cancel.

US Curriculum Gaps

Note for NRI/OCI students studying abroad.

Cross Product Direction Under Speed Pressure

Many school courses discuss magnetic force conceptually, but NEET expects very fast sign-sensitive direction work for positive versus negative charges and for circular versus helical motion.

  • reversing direction for electron motion
  • splitting velocity into parallel and perpendicular components

Device-Level Applications from One Force Law

Velocity selector, cyclotron, and Hall effect are often taught as separate devices, while NEET expects them to be solved as direct consequences of the same Lorentz-force framework.

  • force balance qE = qvB in crossed fields
  • cyclotron frequency independent of orbital speed

Concept IQ Check

Exam-style checks
1A positively charged particle enters a uniform magnetic field with velocity parallel to the field. What happens to its motion?Trajectory
It moves in a circle.
It moves in a helix.
It continues in a straight line with unchanged speed.
It comes to rest.
When velocity is parallel to the magnetic field, the angle theta is 0 degree and the magnetic force qvB sin theta becomes zero. With no magnetic force there is no curvature of the path, so the particle continues straight with unchanged speed. The wrong options come from forgetting that magnetic bending requires a velocity component perpendicular to the field. NEET uses this as a first filter to see whether students classify the geometry correctly before touching formulas.
2In a velocity selector, the electric field is 3 x 10^4 N/C and the magnetic field is 0.015 T. Which speed passes undeviated?Selector
2 x 10^5 m/s
2 x 10^6 m/s
4.5 x 10^6 m/s
5 x 10^2 m/s
For undeflected motion in a selector, electric and magnetic forces must cancel: qE = qvB. Therefore v = E/B = (3 x 10^4)/(0.015) = 2 x 10^6 m/s. The distractors reflect common arithmetic slips such as multiplying E and B or mishandling powers of ten. This is a standard NEET application because it checks both the correct condition and fast unit-safe calculation.

NEET Practice Questions

Click "Reveal Answer" after attempting
1A charged particle enters a uniform magnetic field perpendicular to it. Which quantity remains unchanged during the motion?
velocity direction
kinetic energy
linear momentum direction
centripetal acceleration direction
๐Ÿ‘ Reveal Answer
Kinetic energy. In a pure magnetic field the force is always perpendicular to velocity, so the field changes only the direction of motion and never does work on the particle. Therefore the speed and kinetic energy remain constant, even though the direction of velocity, momentum, and acceleration keep changing around the circular path.
2A proton and an alpha particle enter the same uniform magnetic field perpendicularly with the same speed. Which one has the larger radius of circular path?
proton
alpha particle
both have the same radius
cannot be decided without electric field
๐Ÿ‘ Reveal Answer
Alpha particle. The radius is r = mv/qB, so for the same v and B the ratio depends on m/q. An alpha particle has about four times the proton mass and twice the charge, so its m/q is about twice that of a proton. Therefore its circular orbit radius is larger by a factor of about 2.
3The cyclotron frequency of a charged particle in a given magnetic field depends on:
speed only
radius only
charge-to-mass ratio and magnetic field
kinetic energy only
๐Ÿ‘ Reveal Answer
Charge-to-mass ratio and magnetic field. In the school-level cyclotron formula, nu = qB/2pi m, so the frequency depends on q, B, and m but not on orbital radius or speed. This independence is the reason a fixed alternating frequency can keep accelerating the ion while its orbit grows outward.
4A charged particle enters a uniform magnetic field at an angle other than 0 degree, 90 degree, or 180 degree. Its path is:
straight line
parabola
helix
ellipse
๐Ÿ‘ Reveal Answer
Helix. The velocity has one component parallel to the magnetic field and another perpendicular to it. The perpendicular component causes circular motion, while the parallel component keeps carrying the particle forward, so the combined path is a helix.
5In a Hall-effect setup, the transverse emf appears because charge carriers are:
heated by current
deflected sideways by magnetic force
accelerated along the wire by gravity
annihilated at the surface
๐Ÿ‘ Reveal Answer
Deflected sideways by magnetic force. Moving charge carriers experience a magnetic force perpendicular to both their drift velocity and the magnetic field, so they pile up on one side of the conductor and create a transverse potential difference. That sideways separation is the physical origin of Hall voltage.

Physics Revision Checklist

Check off chapters as you revise

Use this section for quick chapter tracking before mocks, part tests, and final NEET revision.

Tip: Mark a chapter complete only after revising formulas, solving PYQs, and reviewing your error log for that chapter.

Frequently Asked Questions

Notes ยท Downloads ยท Revision ยท Important Questions
Why does a magnetic field not change the speed of a charged particle?
Because magnetic force is always perpendicular to the instantaneous velocity in the pure magnetic case. A perpendicular force changes direction of motion but does no work, so the speed and kinetic energy remain unchanged.
When does the path become a straight line in a magnetic field?
The path is straight when the magnetic force is zero, which happens if B = 0, q = 0, v = 0, or the particle moves parallel or antiparallel to the magnetic field so that sin theta becomes zero.
Why is the time period of circular motion independent of speed?
For perpendicular entry, the magnetic force gives qvB = mv squared over r, which leads to r = mv/qB. Substituting that radius into T = 2pi r/v removes v and gives T = 2pi m/qB.
How do I decide the force direction for a negative charge?
First find the direction of v x B for a positive charge, then reverse that direction for a negative charge. This two-step method is safer than trying to memorise a separate rule for electrons.
What is the physical idea behind a velocity selector?
A selector uses crossed electric and magnetic fields so that one chosen speed experiences equal and opposite electric and magnetic forces. That particle then passes straight while all other speeds bend.
Why can a cyclotron accelerate only charged particles?
Both the magnetic bending force and the electric accelerating force are proportional to charge q. If q is zero, as for a neutron, neither effect exists and the device cannot guide or accelerate the particle.
What does Hall effect tell us in exam problems?
Hall effect shows that moving charge carriers are deflected sideways in a magnetic field, creating a transverse emf. From the sign and magnitude of that emf, one can infer the nature and number density of charge carriers.
What is the most common trap in helical-motion questions?
Students often use the full speed v in every relation. In reality, only the component perpendicular to the field sets the circular radius, while the component parallel to the field decides the pitch and forward motion of the helix.
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Lorentz Force and Trajectory

Velocity Selector and Cyclotron

Subtopics

Lorentz Force and Trajectory

Velocity Selector and Cyclotron

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Force on Charged Particle in Magnetic Field > Velocity Selector and Cyclotron > Hall Effect
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