100k Followers100k500k Followers500k+1 (510) 706-9331+1 (510) 706-9331
Schedule Your Free Exam Readiness Analysis Session!
Testprepkart Logo
Sign InEnroll NowEnroll
Select an exam to view its content.
  • Blog
  • Download
  • Course
  • Result
  • Video Library
  • Pages
  • Notifications

Loading...

Preparing content

Testprepkart Logo

Enabling students prepare and crack toughest examinations worldwide for over a decade with problem solving aptitude!

Contact Us

Useful Links

  • Connect With Counselor
  • University Admissions
  • Prime Videos
  • Enrollment Form
  • Online Fee Payment
  • Testprepkart Operations
  • Faculty Registration

Our Company

  • Contact Us
  • Work With Us
  • Blogs
  • Facultie
  • Partner

Contact Details

  • Phone: +91 0120 4525484
  • Whatsapp: +1 (510) 706-9331
  • Admission: +91 8800123492
  • E-mail: info@testprepkart.com
  • Head Office: F 377, Sector 63, Noida, Uttar Pradesh, India

Copyright ยฉ 2024 CounselKart Educational Services Pvt. Ltd.. All Rights Reserved

Terms of service|Privacy policy|Refund Policy|Login & Register

Scales of Temperature

NEET > Physics > Properties of Bulk Matter > Thermometry, Thermal Expansion and Calorimetry > Scales of Temperature

Unit Progress

0%

Overview content

NEET Physics - Thermometry, Thermal Expansion and Calorimetry

Scales of Temperature โ€“ Complete Notes, Revision, Important Questions & Downloads

Scales of Temperature in this chapter is built around the single TOC subtopic Fixed Points and Temperature Scales, where the book defines lower fixed point, upper fixed point, triple point of water, and the linear relation between Celsius, Fahrenheit, Kelvin, Reaumur, and Rankine readings. NEET usually tests this topic through direct conversion, equal-reading questions, or a new linear scale whose ice point and steam point are given. You must remember the fixed-point table and then use the same linear identity for every scale instead of memorising separate formulas. For example, 68 F corresponds to 20 C, 293.15 K, and 16 R because C/5 = (F-32)/9 = (K-273.15)/5 = R/4.

โฌ‡ Download Notes PDFView Important Questions โ†’
10 SubtopicsLinear Conversion MCQsThermometry Foundation
Expected QuestionsQ
0-1
A standalone NEET question is not guaranteed every year, but scale-conversion logic is a recurring one-step insert inside thermometry and heat questions.
Time Requiredโฑ
45-60 min
One short theory pass for the fixed points and one practice set covering direct conversion, equal-reading, and new-scale mapping is usually enough.
Difficultyโšก
Easy-Medium
The algebra is linear, but students lose marks when they mix up the zero points of the scales or treat a temperature interval like an absolute reading.
NRI USA Curriculum GapUS
Medium
US school physics often uses Celsius and Kelvin only, so NEET-style questions involving Fahrenheit, Reaumur, Rankine, or a newly invented linear scale can feel unfamiliar even when the math is simple.
10Subtopics
4Practice Questions
4Free Downloads
45-60 minPrep Time
โฌ‡ Get Free Downloads

NEET Weightage - Scales of Temperature

Thermometry, Thermal Expansion and Calorimetry (Chapter 12)
NEET YearQuestions from this TopicBarMarks
20240
ย 
0 Q
0
20230
ย 
0 Q
0
20220
ย 
0 Q
0
20210
ย 
0 Q
0
20200
ย 
0 Q
0
20190
ย 
0 Q
0
6-Year Direct-Question Snapshot (2019-2024)0ย 0
Direct stand-alone NEET questions on Scales of Temperature are irregular; the topic is more often used as a conversion step inside thermometry or heat questions.
Questions usually reduce to the same fixed-point identity, so memorising one linear relation is more useful than memorising many isolated conversions.

The fastest marks come from separating absolute readings from temperature intervals: a change of 25 C equals a change of 25 K but equals 45 F.
๐Ÿ“Š
~0 direct
Avg Questions / Year
๐ŸŽฏ
0 direct
Total Marks (6 yrs)
๐Ÿ“ˆ
Indirect
Pattern
โš ๏ธ
Easy
Difficulty

Exam Strategy for Scales of Temperature

1

Lock the fixed points first Memorise the lower fixed point and upper fixed point for Celsius, Fahrenheit, Kelvin, Reaumur, and Rankine before you start solving. Check whether the question uses ice point and steam point or a different reference. The trap is plugging 0 and 100 into every scale even when Fahrenheit or Rankine is given. Recognise this topic whenever a thermometer question lists two calibration points.

2

Use one linear identity for every conversion Write (reading - LFP)/(UFP - LFP) for the given scale and the target scale instead of hunting for a memorised shortcut. Check that the numerator uses the correct zero point, such as F-32 or Ra-460. The trap is writing F/9 instead of (F-32)/9. This topic is hiding inside any new-scale problem with freezing and boiling points provided.

3

Separate absolute temperature from temperature difference Memorise that Kelvin and Celsius have equal size intervals, so delta T in C equals delta T in K. Check whether the question asks for a reading or for a rise in temperature. The trap is adding 273.15 to a temperature difference. Recognise this version when words like increase, fall, or difference appear.

4

Handle Kelvin carefully Memorise K = C + 273.15 for readings and remember that zero kelvin is absolute zero. Check whether the question is about school-level conversion or the reference discussion around the triple point of water. The trap is treating 273.16 K as the zero of the Kelvin scale; it is a reference temperature, not the zero reading. This shows up when the statement mixes thermometry language with scale conversion.

5

Practice equal-reading and odd-scale questions Memorise the classic equal-reading result C = F at -40 and solve at least one invented scale problem where the fixed points are non-standard. Check that your relation stays linear from LFP to UFP. The trap is using direct proportion without shifting by the lower fixed point. Recognise this topic immediately when a question defines a fresh scale like X, Y, or W.

Download Study Notes - Scales of Temperature

PDF ยท Cheat Sheet ยท MCQ Set ยท PYQ
๐Ÿ“˜
Scales of Temperature - Full Notes
Complete notes covering fixed points, Celsius-Fahrenheit-Kelvin-Reaumur-Rankine calibration, the general conversion identity, and one worked example for each common conversion type.
10 subtopicsWorked examplesScale table included
Download PDF
๐Ÿ“—
Scales of Temperature - Formula Sheet
One-page sheet with LFP-UFP values for all five scales, C/5 = (F-32)/9 = (K-273.15)/5 = R/4, and the interval rule delta T in C = delta T in K.
1 pageAll key formulas
Download PDF
๐Ÿ“™
Scales of Temperature - MCQ Practice
Practice set focused on direct conversion, equal-reading questions, new thermometer scales, and interval-versus-reading traps that commonly appear in temperature-scale MCQs.
12 MCQsDetailed solutions
Download PDF
๐Ÿ“•
Scales of Temperature - PYQ
Revision pack of NEET-style and legacy medical-entrance conversion questions built around fixed points, equal readings, and custom linear scales so you can rehearse the exact algebra used in exam settings.
NEET-styleAnswer key included
Download PDF

Subtopics in Scales of Temperature

2-Column Table
Column AColumn B
Fixed Points and Temperature Scalesโ†—
Length of liquid in capillaryโ†—
Pressure of gas at constant volumeโ†—
Volume of gas at constant pressureโ†—
Resistance of a given platinum wireโ†—
Constant pressure gas thermometersโ†—
Kelvin scaleโ†—
All these temperaturesโ†—
Liquid (mercury) thermometersโ†—
Mercury thermometer with cylindrical bulbsโ†—

Rapid Revision - Scales of Temperature

Concept โ†’ Trap โ†’ Example

1) Fixed Points and Temperature Scales

Calibration + Conversion

For any linear temperature scale, (reading - LFP)/(UFP - LFP) is the same constant; hence C/5 = (F-32)/9 = (K-273.15)/5 = R/4 and Celsius-Kelvin intervals are equal.

  • Start every problem by writing the lower fixed point and upper fixed point of the scale that appears in the question before substituting numbers.
  • If the question asks for a rise or fall in temperature, use interval conversion only: a change of 1 C equals a change of 1 K but equals 9/5 F.
  • Common NEET trap: students treat Fahrenheit and Rankine like zero-based scales and forget to subtract 32 or 460 before forming the linear ratio.
Example (NEET-style)Convert 68 F to Celsius: (C-0)/100 = (68-32)/180 gives C = 20. Then K = 20 + 273.15 = 293.15 K and Reaumur reading is R = 4C/5 = 16. The same fixed-point logic works because each scale is linear between the ice point and steam point.

US Curriculum Gaps - Scales of Temperature

Students coming from US high-school courses usually know Celsius and Kelvin, but NEET asks for faster multi-scale conversion and custom linear-scale setup.

AP Physics 1 / Honors Physics rarely use five-scale calibration tables

US introductory physics courses usually stay with Celsius and Kelvin for laboratory work, so students may not have automatic recall of Fahrenheit, Reaumur, and Rankine fixed points. NEET expects you to move between named scales and still keep the algebra clean.

  • Memorise the two calibration points of Fahrenheit, Reaumur, Rankine, and Kelvin alongside Celsius instead of treating them as optional facts.
  • Practise questions where the target unit is not Kelvin or Celsius, because NEET can ask directly for Fahrenheit or a custom scale.
  • Keep one fixed-point table in your notes so you can rebuild every conversion from first principles.

Algebra 2 / Integrated Math III seldom connect linear functions to thermometer scales

US math courses teach linear interpolation abstractly, but NEET temperature-scale questions expect you to build that line instantly from the ice point and steam point. The mathematical step is easy; the exam difficulty is recognising the calibration structure quickly.

  • Translate every new scale into slope-plus-shift language using its LFP and UFP rather than guessing a direct proportion.
  • Solve at least one equal-reading question and one custom-scale question so the shift term becomes automatic.
  • Check whether the question asks for an absolute reading or a change in temperature before using the line.

NEET-style Practice Questions - Scales of Temperature

4 NEET-style practice questions
1A thermometer reads 95 F for a patient's sample. The same temperature on the Celsius scale is:NEET-style practice
30 C
35 C
37 C
40 C
Use the fixed-point relation C/5 = (F-32)/9. Substituting F = 95 gives C/5 = 63/9 = 7, so C = 35. Option 2 is correct. Option 1 comes from subtracting 32 and forgetting the factor 5/9. Option 3 is a common clinical-temperature distractor because students remember 98.6 F = 37 C and then round everything near that value. Option 4 is what you get if you use F/9 directly and ignore the shift of 32 F at the lower fixed point. The full reasoning is linear calibration, not direct proportion from zero.
2On a new linear scale X, the freezing point of water is 20 X and the boiling point is 170 X. What is the reading on this scale for 40 C?NEET-style practice
70 X
80 X
90 X
100 X
Write the linear identity using the lower and upper fixed points: (X-20)/(170-20) = (40-0)/(100-0). This gives (X-20)/150 = 40/100 = 2/5, so X-20 = 60 and X = 80. Option 2 is correct. Option 1 uses only the slope and forgets to add the lower fixed-point shift of 20 X. Option 3 comes from treating the temperature as 40 percent of 170 rather than 40 percent of the interval 150. Option 4 is the result of assuming the scale starts at zero. New-scale questions are solved only after removing the offset.
3At what temperature do Celsius and Fahrenheit thermometers show the same numerical reading?NEET-style practice
-40
-32
0
40
Let the common reading be t. Then t/5 = (t-32)/9. Cross-multiplying gives 9t = 5t - 160, so 4t = -160 and t = -40. Option 1 is correct. Option 2 is a trap based on the Fahrenheit lower fixed point 32 F and has nothing to do with equal readings. Option 3 is wrong because 0 C corresponds to 32 F, not 0 F. Option 4 ignores the negative sign that appears naturally from the algebra. Equal-reading questions are standard tests of whether you can keep the shift term and sign consistent.
4A liquid is heated so that its temperature rises by 25 C. The corresponding rise on the Fahrenheit scale is:NEET-style practice
25 F
32 F
45 F
57 F
This is an interval question, so do not use absolute fixed points directly. Since 100 C corresponds to 180 F, a rise of 1 C corresponds to 9/5 F. Therefore a rise of 25 C corresponds to 25 x 9/5 = 45 F. Option 3 is correct. Option 1 incorrectly assumes Celsius and Fahrenheit intervals are equal. Option 2 confuses a change in reading with the 32 F offset at the lower fixed point. Option 4 comes from adding 32 to the interval, which is never done. The key is to identify that this is delta T, not a thermometer reading from zero.

Practice Problems - Scales of Temperature

Click "Reveal Answer" after attempting
1A laboratory sample is at 310.15 K. What are its readings on the Celsius and Fahrenheit scales?
37 C and 98.6 F
35 C and 95 F
40 C and 104 F
27 C and 80.6 F
๐Ÿ‘ Reveal Answer
Option 1 is correct. First convert Kelvin to Celsius: C = 310.15 - 273.15 = 37 C. Then convert Celsius to Fahrenheit using F = 9C/5 + 32 = 9 x 37/5 + 32 = 66.6 + 32 = 98.6 F. The other options either use the wrong Kelvin offset or apply the Fahrenheit formula without converting correctly from Kelvin.
2On the Reaumur scale the ice point is 0 R and the steam point is 80 R. What is the Reaumur reading corresponding to 50 C?
32 R
36 R
40 R
45 R
๐Ÿ‘ Reveal Answer
Option 3 is correct. Use C/100 = R/80 because both scales are measured from their lower fixed point. Thus R = 80 x 50/100 = 40. You can also use the shortcut R = 4C/5. The wrong options come from treating 80 as the slope directly without dividing by the Celsius interval 100 or from mixing Fahrenheit numbers into the relation.
3A new thermometer scale Y reads 15 Y at the freezing point of water and 115 Y at the boiling point. What temperature in Celsius corresponds to a reading of 65 Y?
45 C
50 C
55 C
60 C
๐Ÿ‘ Reveal Answer
Option 2 is correct. Use (Y-15)/(115-15) = C/100. For Y = 65, (65-15)/100 = C/100, so 50/100 = C/100 and C = 50. The key step is subtracting the lower fixed point 15 Y before comparing the interval with the Celsius interval. Direct proportion from 65 to 115 gives the wrong result.
4If the temperature of a gas falls from 80 C to 20 C, what is the fall in temperature on the Kelvin and Fahrenheit scales?
60 K and 60 F
60 K and 108 F
353.15 K and 68 F
60 K and 92 F
๐Ÿ‘ Reveal Answer
Option 2 is correct. The fall in Celsius is 80 - 20 = 60 C. A temperature interval is identical in Celsius and Kelvin, so the fall is 60 K. On the Fahrenheit scale, delta F = 9/5 x delta C = 9/5 x 60 = 108 F. The wrong options either assume equal interval size for Fahrenheit or confuse the interval with the absolute Kelvin reading.

Physics - Scales of Temperature Revision Checklist

Check off chapters as you revise

Use this section for quick chapter tracking before mocks, part tests, and final NEET revision.

Tip: Mark a chapter complete only after revising formulas, solving PYQs, and reviewing your error log for that chapter.

Frequently Asked Questions - Scales of Temperature

Notes ยท Downloads ยท Revision ยท Important Questions
Why are two fixed points used to define a temperature scale?
A linear thermometer scale needs two calibration anchors so that both the zero shift and the size of one division are fixed. The freezing point of water gives the lower fixed point and the boiling point gives the upper fixed point under standard atmospheric pressure. Once those two points are marked, every intermediate reading is found by linear interpolation.
Why do Celsius and Kelvin have the same interval size?
Celsius and Kelvin differ only by a shift in the zero point. A change of 1 C corresponds to a change of 1 K because both scales have the same size degree; only their origins are different. That is why reading conversion uses K = C + 273.15, but interval conversion uses delta K = delta C with no added constant.
Why is 0 C not the lowest possible temperature?
Zero degree Celsius is only the ice point on the Celsius scale. The OCR pages themselves note that temperature cannot be lowered without limit and that the Kelvin scale has a theoretical zero. In school-level physics, this lower limit is 0 K, called absolute zero, which lies 273.15 units below 0 C.
What is the triple point of water and why is it mentioned in thermometry?
The triple point of water is the unique state where solid, liquid, and vapour coexist in equilibrium. It is a very reproducible reference temperature, written in the OCR page as 273.16 K = 0.01 C, so thermometry discussions use it as a precise calibration reference. For NEET conversions, you mainly need to remember that the Kelvin scale itself starts at absolute zero and that triple-point data provide a calibration benchmark.
When should I use 273 and when should I use 273.15 in Kelvin conversion?
For fast NEET numericals, K = C + 273 is often accepted when the problem is not built around decimal precision. If the data are given with decimal accuracy, or if you are comparing close values, use 273.15 because that is the more accurate relation. In either case, do not add the constant when the question asks only for a temperature difference.
Why does Fahrenheit have 180 divisions between the fixed points while Celsius has 100?
The Fahrenheit scale was historically calibrated differently, so the interval between the freezing point and boiling point of water spans 180 equal divisions instead of 100. That immediately gives the slope relation 100 C equivalent to 180 F, which simplifies to 5 C equivalent to 9 F. Nearly every Celsius-Fahrenheit conversion formula is just this slope plus the 32 F offset at the lower fixed point.
How do I solve a question on a completely new temperature scale?
Treat the new scale exactly like Celsius or Fahrenheit: identify its lower fixed point and upper fixed point, then form the ratio (reading - LFP)/(UFP - LFP). Set that equal to the same ratio for the target scale and solve the resulting linear equation. Students lose marks only when they assume the new scale starts from zero and skip subtracting the lower fixed point.
Why do Celsius and Fahrenheit show the same number at -40?
Because the two scales are linear with different slopes and different zero points, their graphs intersect once. Set the two readings equal to t and solve t/5 = (t-32)/9. The algebra gives 9t = 5t - 160, so t = -40. This is a useful checkpoint in MCQs because it confirms that the Fahrenheit shift has been handled correctly.
What is the most common mistake in temperature-scale MCQs?
The most common mistake is mixing absolute readings with intervals. Students correctly remember K = C + 273.15 and then incorrectly add 273.15 to a temperature rise, or they convert a Fahrenheit reading using F/9 instead of (F-32)/9. The safest method is to decide first whether the question is asking for a reading or for a change, and then write the appropriate linear relation before substituting values.
For NRI / OCI / U.S.-Based Families

NEET NRI Counseling & Admission eBook Download

A practical guide covering sponsor rules, document checklist, verification traps, NRI quota reality, and step-by-step counselling flow. Designed to prevent last-minute rejections and wrong choice filling.

Sponsor + Proof ClarityDocuments ChecklistState-wise Traps
โ†“ Download eBook (PDF)โ†’ See What's Inside
Tip: Keep this eBook open during verification + choice filling week for quick cross-checking.
NEET Prep (India + NRI-USA)

Schedule Trial Session For NEET Prep

Get a short diagnostic + study roadmap: syllabus gaps (NCERT vs U.S. curriculum), weak chapters, and the exact weekly plan needed to improve accuracy under time.

Gap MappingWeekly PlanAccuracy Fix
โ†’ Book Trial Sessionโ†’ WhatsApp Us
Best for: Students in Grade 10โ€“12 (U.S. / India) who want a clear NEET timeline and daily practice structure.

Fixed Points and Temperature Scales

Length of liquid in capillary

Pressure of gas at constant volume

Volume of gas at constant pressure

Resistance of a given platinum wire

Constant pressure gas thermometers

Kelvin scale

All these temperatures

Liquid (mercury) thermometers

Mercury thermometer with cylindrical bulbs

Subtopics

Fixed Points and Temperature Scales

Length of liquid in capillary

Pressure of gas at constant volume

Volume of gas at constant pressure

Resistance of a given platinum wire

Constant pressure gas thermometers

Kelvin scale

All these temperatures

Liquid (mercury) thermometers

Mercury thermometer with cylindrical bulbs

Previous
Scales of Temperature > Mercury thermometer with cylindrical bulbs > Mercury thermometer with cylindrical bulbs
Next
Fixed Points and Temperature Scales

Loading tests...

NEET > Physics > Properties of Bulk Matter Chapters

Review your status and progress for each chapter in this unit. Use the slider to set progress or click "Mark as Done" to complete.

ChapterStatusProgress

Elasticity

Weightage: 02.2K
0%

Surface Tension

Weightage: 02.2K
0%

Fluid Mechanics

Weightage: 02.2K
0%

Thermometry, Thermal Expansion and Calorimetry

Weightage: 02.2K
0%

Transmission of Heat

Weightage: 02.2K
0%

Comments

Leave a comment

0/2000Comments are moderated

You can comment without logging in. We'll ask for your name and email before submitting.

Comments (0)

No comments yet. Be the first to comment!