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Law of Equipartition of Energy (Boltzmann Law)

NEET > Physics > Behaviour of Perfect Gas and Kinetic Theory > Kinetic Theory of Gases > Law of Equipartition of Energy (Boltzmann Law)

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NEET Physics - Kinetic Theory of Gases

Law of Equipartition of Energy (Boltzmann Law) โ€“ Complete Notes, Revision, Important Questions & Downloads

This topic is applied through one TOC subtopic, Statement and Applications, where NEET tests direct conversion of degrees of freedom into energy and heat-capacity relations. The operational rule is that each quadratic mode contributes (1/2)kT per molecule, so total energy is U = (f/2)NkT or U = (f/2)RT per mole. Typical NEET stems combine molecular type (monoatomic, diatomic, non-linear triatomic) with f-values and ask for U, C_v, C_p, or gamma without giving long derivations. For example, for a rigid diatomic gas at room temperature, f = 5 gives U = (5/2)RT and then C_v = (5/2)R, C_p = (7/2)R.

โฌ‡ Download Notes PDFView Important Questions โ†’
7 SubtopicsFormula-DrivenHeat-Capacity Link
Expected QuestionsQ
1
Usually appears as a direct formula application from degree-of-freedom data in NEET and recent re-tests.
Time Requiredโฑ
45-60 min
Memorise the f table and drill 20-25 conversion problems from f -> U -> C_v/C_p/gamma.
Difficultyโšก
Medium
Concept is short, but mistakes in counting rotational/vibrational modes cause option traps.
NRI USA Curriculum GapUS
Medium
US high-school physics usually treats kinetic theory qualitatively; NEET requires quick symbolic conversion using f-based thermodynamic formulas.
7Subtopics
6Practice Questions
4Free Downloads
45-60 minPrep Time
โฌ‡ Get Free Downloads

NEET Weightage - Law of Equipartition of Energy (Boltzmann Law)

Kinetic Theory of Gases (Chapter 13)
NEET YearQuestions from this TopicBarMarks
20241
ย 
1 Q
4
20231
ย 
1 Q
4
20220
ย 
0 Q
0
20211
ย 
1 Q
4
20201
ย 
1 Q
4
20191
ย 
1 Q
4
6-Year Snapshot (2019-2024)5-7ย 20-28
Equipartition questions are frequently attached to degree-of-freedom identification: monatomic f=3, rigid diatomic f=5, non-linear triatomic f=6, linear triatomic f=5 (without vibrational activation).
The fastest path is f -> U = (f/2)RT -> C_v = (f/2)R -> C_p = C_v + R -> gamma = C_p/C_v.

Question setters often include statements on vibration at higher temperature; if vibrational modes are active, each vibrational mode contributes both kinetic and potential parts.
๐Ÿ“Š
0.8-1.2
Avg Questions / Year
๐ŸŽฏ
20-28
Total Marks (6 yrs)
๐Ÿ“ˆ
Direct
Pattern
โš ๏ธ
Medium
Difficulty

How To Solve Equipartition Questions Reliably

1

Lock the f-values before calculation Write f first from molecular structure assumptions in the question. For a rigid diatomic gas use f=5 at ordinary temperature; do not add vibrational terms unless activation is explicitly implied.

2

Convert in one chain: f to U to heat capacities Use U = (f/2)RT per mole, then C_v = (dU/dT) = (f/2)R, then C_p = C_v + R. This avoids mixing formulas from unrelated chapters.

3

Check which energy equation is being asked If the stem uses pV=(2/3)E, remember E there is translational kinetic part for ideal-gas pressure relation; rotational and vibrational terms are handled via equipartition in internal-energy expressions.

4

Use gamma sanity check After computing C_p and C_v, verify gamma > 1 and typical values (5/3 for monoatomic, 7/5 for rigid diatomic). This catches arithmetic and mode-count errors quickly.

5

Scan for vibrational activation clue words Phrases like high temperature or vibrational mode active mean extra contributions; each vibrational mode adds two quadratic terms, so ignoring this leads to wrong C_v and gamma options.

Download Study Notes - Law of Equipartition of Energy (Boltzmann Law)

PDF ยท Cheat Sheet ยท MCQ Set ยท PYQ
๐Ÿ“˜
Law of Equipartition of Energy - Full Notes
Complete notes on statement, degree-of-freedom mapping, molecular energy formulas, and conversion to C_v, C_p, gamma with solved NEET-style cases.
Concept mapSolved casesExam traps
Download PDF
๐Ÿ“—
Law of Equipartition of Energy - Formula Sheet
One-page sheet with U=(f/2)RT, C_v=(f/2)R, C_p=((f/2)+1)R, gamma formulas, key conditions, and one worked example per subtopic.
1 pageFormula-first
Download PDF
๐Ÿ“™
Law of Equipartition of Energy - MCQ Practice
Targeted MCQs on degree-of-freedom counting, internal energy change, and C_p/C_v ratio conversion with stepwise explanations.
30 MCQsDetailed keys
Download PDF
๐Ÿ“•
Law of Equipartition of Energy - NEET-Style PYQ Practice
NEET-style mixed set emphasising rigid vs non-rigid molecule assumptions, vibrational activation clues, and gamma-based elimination.
NEET-styleRevision set
Download PDF

Subtopics in Law of Equipartition of Energy (Boltzmann Law)

2-Column Table
Column AColumn B
Statement and Applicationsโ†—
Translational degree of freedomโ†—
Rotational degree of freedomโ†—
Vibrational degree of freedomโ†—
Monoatomic gasโ†—
Diatomic gasโ†—
Triatomic gas (Non-linear)โ†—

Rapid Revision - Law of Equipartition of Energy (Boltzmann Law)

Concept โ†’ Trap โ†’ Example

1) Statement and Applications

Core Law + Usage

In thermal equilibrium, each quadratic degree of freedom contributes (1/2)kT per molecule, so average molecular energy is (f/2)kT and molar internal energy is (f/2)RT.

  • Use this law only after identifying active degrees of freedom from molecular model and temperature condition.
  • For rigid molecules at ordinary temperature, translational and rotational terms dominate; vibrational activation is usually excluded unless stated.
  • Common NEET trap: directly substituting f from memory without checking whether the molecule is linear/non-linear and whether vibration is considered.
Example (NEET-style)For one mole of rigid diatomic gas at temperature T, f=5 so U=(5/2)RT. At T=300 K, U=(5/2)(8.314)(300) approximately 6.24 kJ per mole. Then C_v=(5/2)R and C_p=(7/2)R.

US Curriculum Gaps - Law of Equipartition of Energy (Boltzmann Law)

NRI students often need a bridge from conceptual gas-kinetic treatment to formula-heavy NEET conversion speed.

AP Physics 1 / AP Physics C rarely tests full f-to-gamma conversion chains

US AP courses typically emphasize conceptual kinetic theory and ideal-gas process reasoning, but NEET routinely asks direct symbolic conversion from degree of freedom to U, C_v, C_p, and gamma in one step.

  • Students may know kinetic theory ideas but not automatic mapping U=(f/2)RT and C_v=(f/2)R.
  • NEET options are close; speed requires immediate formula chaining, not long derivation.
  • Practice timed sets where the first line is always the chosen f-value and assumption.

US high-school tracks underemphasize rotational-vibrational activation assumptions

Many school-level US resources discuss degrees of freedom qualitatively, while NEET MCQs exploit whether vibrational modes are active and whether molecule geometry is linear or non-linear.

  • Wrong assumption about vibration changes f and therefore all downstream answers.
  • Rigid diatomic at room temperature generally uses f=5 in NEET-level modeling.
  • Create a one-page assumption table: monoatomic, rigid diatomic, linear triatomic, non-linear triatomic.

Concept IQ Check - Law of Equipartition of Energy (Boltzmann Law)

4 concept-application MCQs
1A rigid diatomic ideal gas is at temperature T. Using equipartition, the internal energy per mole is:Statement and Applications
(3/2)RT
2RT
(5/2)RT
3RT
For a rigid diatomic molecule at ordinary temperature, active degrees are 3 translational + 2 rotational, so f=5. Equipartition gives average energy per molecule as (f/2)kT and per mole as U=(f/2)RT. Therefore U=(5/2)RT, so option (c) is correct. Option (a) corresponds to monoatomic gas with f=3. Option (b) implies f=4, not a standard rigid-molecule case here. Option (d) implies f=6, which would fit non-linear triatomic rigid molecules, not rigid diatomic.
2For an ideal gas with f degrees of freedom, C_v and C_p are respectively (f/2)R and ((f/2)+1)R. The ratio gamma is:Statement and Applications
1 + (1/f)
1 + (2/f)
f/2
2 + f
Start with gamma = C_p/C_v. Substituting, gamma = [((f/2)+1)R]/[(f/2)R] = ((f+2)/2)/(f/2) = (f+2)/f = 1 + 2/f. So option (b) is correct. Option (a) comes from dropping one factor of 2 incorrectly while simplifying. Option (c) is just C_v/R and not a ratio of specific heats. Option (d) has wrong dimensional form and ignores division structure. In NEET, this algebraic simplification is often asked after giving molecular type so you can then plug f immediately.
3A non-linear triatomic ideal gas (rigid model) has f = 6. Its molar C_v from equipartition is:Statement and Applications
(3/2)R
(5/2)R
3R
4R
Equipartition for ideal gas gives C_v=(f/2)R. For non-linear triatomic rigid molecules, f=6, so C_v=(6/2)R=3R. Therefore option (c) is correct. Option (b) corresponds to f=5 (rigid diatomic or linear triatomic). Option (a) corresponds to f=3 monoatomic gas. Option (d) would be C_p if C_v=3R because C_p=C_v+R=4R. Many students misread C_v as C_p in such option sets; always mark the asked quantity before substitution.
4For one mole of gas, internal energy increases by 6.24 kJ when temperature rises by 300 K. Using R=8.314 J mol^-1 K^-1 and equipartition, the most likely f is:Statement and Applications
3
5
6
7
From equipartition, for one mole Delta U = (f/2)R Delta T. Rearranging, f = 2 Delta U/(R Delta T). Use Delta U = 6.24 kJ = 6240 J, Delta T = 300 K: f = 2 x 6240/(8.314 x 300) approximately 12480/2494.2 approximately 5.0. Hence option (b) is correct. Option (a) would give Delta U around 3.74 kJ; option (c) gives about 7.48 kJ; option (d) gives about 8.73 kJ. This style appears in NEET to test formula inversion rather than direct forward substitution.

Practice Problems - Law of Equipartition of Energy (Boltzmann Law)

Click "Reveal Answer" after attempting
1For a monoatomic ideal gas, find C_p/C_v using equipartition.
5/3
7/5
4/3
3/2
๐Ÿ‘ Reveal Answer
Correct option: 5/3. For monoatomic gas, f=3 (three translational modes). So C_v=(f/2)R=(3/2)R. Then C_p=C_v+R=(3/2)R+R=(5/2)R. Therefore gamma=C_p/C_v=[(5/2)R]/[(3/2)R]=5/3. The options 7/5 and 4/3 correspond to higher f-values (5 and 6 respectively), not monoatomic.
2A rigid diatomic ideal gas is heated by 120 K. Find Delta U per mole in terms of R.
120R
240R
300R
420R
๐Ÿ‘ Reveal Answer
Correct option: 300R. For rigid diatomic gas f=5. Equipartition gives Delta U=(f/2)R Delta T=(5/2)R(120)=300R. Option 120R corresponds to f=2 (not physical here), 240R corresponds to f=4, and 420R corresponds to f=7 with wrong molecular assumption. Always decide f first from the model in the stem.
3For a non-linear triatomic rigid molecule (f=6), calculate gamma.
5/3
7/5
4/3
9/7
๐Ÿ‘ Reveal Answer
Correct option: 4/3. Use gamma = 1 + 2/f. With f=6, gamma=1+2/6=1+1/3=4/3. Equivalent route: C_v=(6/2)R=3R and C_p=4R, so gamma=4R/3R=4/3. Option 5/3 belongs to monoatomic (f=3), 7/5 to rigid diatomic/linear triatomic (f=5), and 9/7 to f=7 where vibrational contributions are active for certain linear molecules at high temperature.
4If C_p - C_v = R and C_v = (5/2)R for an ideal gas, determine f and molecular category under rigid model.
f=3, monoatomic
f=5, rigid diatomic
f=6, non-linear triatomic
f=7, linear triatomic with vibration
๐Ÿ‘ Reveal Answer
Correct option: f=5, rigid diatomic. From C_v=(f/2)R, we get f=5 directly. Under rigid model at ordinary temperature, f=5 corresponds to diatomic molecules (3 translational + 2 rotational) and also linear triatomic rigid case in simplified treatments. In standard NEET framing for this value, the expected identification is rigid diatomic; then C_p=(7/2)R and gamma=7/5 follow immediately.

Physics - Law of Equipartition of Energy (Boltzmann Law) Revision Checklist

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Frequently Asked Questions - Law of Equipartition of Energy (Boltzmann Law)

Notes ยท Downloads ยท Revision ยท Important Questions
What is the shortest correct statement of equipartition for NEET?
In thermal equilibrium, each active quadratic degree of freedom contributes average energy (1/2)kT per molecule. Therefore, if a molecule has f active degrees of freedom, average molecular energy is (f/2)kT and molar internal energy is (f/2)RT. This is the exact form typically required in NEET calculation questions.
Why is f=5 used for rigid diatomic gas at ordinary temperature?
A rigid diatomic molecule has three translational and two rotational active modes in the standard kinetic-theory model at ordinary temperature, giving f=5. The rotation about the internuclear axis is usually neglected due to very small moment of inertia in this level of treatment. Vibrational contribution is generally ignored unless high-temperature activation is explicitly considered.
How do I derive C_v and C_p from equipartition quickly?
Start with U=(f/2)RT for one mole. Differentiate with respect to T at constant volume to get C_v=(dU/dT)=(f/2)R. For ideal gases, C_p-C_v=R, so C_p=((f/2)+1)R. This two-line derivation is enough for most NEET stems and avoids memorizing disconnected formulas.
Which formula gives gamma directly from f?
Use gamma=C_p/C_v=1+2/f. It comes from substituting C_p=((f/2)+1)R and C_v=(f/2)R. For f=3, gamma=5/3; for f=5, gamma=7/5; for f=6, gamma=4/3. These benchmark values are often embedded in options for elimination-based solving.
What is the most common trap in equipartition MCQs?
The most frequent trap is wrong mode counting before substitution. Students often forget to check whether the molecule is linear/non-linear or whether vibration is active. Once f is wrong, every downstream quantity U, C_v, C_p, and gamma becomes wrong but still may look plausible, so the first checkpoint must always be f selection.
Does pV=(2/3)E always represent total internal energy?
In kinetic-theory derivation, that relation links pressure to translational kinetic energy content of molecules. Equipartition-based total internal energy includes all active modes represented by f. So you must read context: for pure translational derivation use pV relation; for thermodynamic state quantities in this topic use U=(f/2)RT.
When do vibrational modes start affecting NEET-level answers?
In school-level NEET treatment, vibrational modes are usually ignored for rigid-molecule assumptions unless the question explicitly indicates high temperature or active vibration. If activated, each vibrational mode contributes two quadratic terms (kinetic plus potential), changing f and all dependent values. This is why wording cues in the stem matter.
How is this topic connected to the next topic, Specific Heat of a Gas?
Equipartition is the theoretical bridge. Once you know how many active modes share energy, you obtain U and then C_v and C_p directly, which is exactly the basis for specific-heat formulas in the next section. In NEET sequence problems, an equipartition calculation in one step is often followed by a specific-heat or gamma inference in the next step.
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Statement and Applications

Translational degree of freedom

Rotational degree of freedom

Vibrational degree of freedom

Monoatomic gas

Diatomic gas

Triatomic gas (Non-linear)

Subtopics

Statement and Applications

Translational degree of freedom

Rotational degree of freedom

Vibrational degree of freedom

Monoatomic gas

Diatomic gas

Triatomic gas (Non-linear)

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Law of Equipartition of Energy (Boltzmann Law) > Triatomic gas (Non-linear) > Triatomic gas (Non-linear)
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